# Difference between revisions of "Chance News 68"

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==Remarkable birthday pattern, or not?== | ==Remarkable birthday pattern, or not?== | ||

− | http://www.usatoday.com/yourlife/parenting-family/babies/2010-10-14-Birthday14_ST_N.htm “Mom’s babies born on 8-8-08, 9-9-09, 10-10-10”]<br> | + | [http://www.usatoday.com/yourlife/parenting-family/babies/2010-10-14-Birthday14_ST_N.htm “Mom’s babies born on 8-8-08, 9-9-09, 10-10-10”]<br> |

by Elizabeth Weise, USA TODAY, October 14, 2010<br> | by Elizabeth Weise, USA TODAY, October 14, 2010<br> | ||

## Revision as of 11:59, 9 November 2010

## Contents

## Quotations

"If you're a politician, admitting you're wrong is a weakness, but if you're an engineer, you essentially want to be wrong half the time. If you do experiments and you're always right, then you aren't getting enough information out of those experiments. You want your experiment to be like the flip of a coin: You have no idea if it is going to come up heads or tails. You want to not know what the results are going to be." Peter Norvig, as quoted at Slate Magazine. Submitted by Steve Simon.

Two quotes from Sir Francis Galton[1]:

“ I know of scarcely anything so apt to impress the imagination as the wonderful form of cosmic order expressed by the 'Law of Frequency of Error.' The law would have been personified by the Greeks and deified, if they had known of it. It reigns with serenity and in complete self-effacement, amidst the wildest confusion. The huger the mob, and the greater the apparent anarchy, the more perfect is its sway. It is the supreme law of Unreason. Whenever a large sample of chaotic elements are taken in hand and marshaled in the order of their magnitude, an unsuspected and most beautiful form of regularity proves to have been latent all along.”

“[Statistics are] the only tools by which an opening may be cut through the formidable thicket of difficulties that bars the path of those who pursue the Science of Man.”

Submitted by Margaret Cibes

## Forsooth

A blogger responded to a John Allen Paulos article in *The New York Times* of October 24, 2010[2]:

”One can't really say anything meaningful about probability without actual data.”

Submitted by Margaret Cibes

## Paulos on probability

“Stories vs. Statistics”

by John Allen Paulos, *The New York Times*, October 24, 2010

In this article, Paulos discusses two classic probability problems, and 143 bloggers[3]respond *en masse*.

PROBLEM 1. With respect to the story of Linda the famous feminist bank teller, Paulos says that, while more details about a fictional character may make the story more believable, “the more details there are in a story, the less likely it is that the conjunction of all of them is true.”

In the classic illustration of the fallacy …, a woman named Linda is described. She is single, in her early 30s, outspoken, and exceedingly smart. A philosophy major in college, she has devoted herself to issues such as nuclear non-proliferation. So which of the following is more likely?

a.) Linda is a bank teller.

b.) Linda is a bank teller and is active in the feminist movement.

Paulos concludes, “Although most people choose b.), this option is less likely since two conditions must be met in order for it to be satisfied, whereas only one of them is required for option a.) to be satisfied.”

PROBLEM 1. Bloggers

No. 10. a.) is not necessarily more likely than b.). Paulos’ “understanding of others is weak,” and we need more information about how her activism may have led to sexual discrimination to answer the question.

No. 20’s response to #10. “Unless you believe that there could not possibly be such a person, Paulos is correct.”

PROBLEM 2, with variations. With respect to the classic two-boy problem, Paulos says that “our judgment of [a] probability is almost always affected by its intensional [sic] context.”

Given that a family has two children and that at least one of them is a boy, what is the probability that both children are boys? The most common solution notes that there are four equally likely possibilities — BB, BG, GB, GG …. Since we’re told that the family has at least one boy, the GG possibility is eliminated and only one of the remaining three equally likely possibilities is a family with two boys. Thus the probability of two boys in the family is 1/3. …. What if instead of being told that the family has at least one boy, we meet the parents who introduce us to their son? Then there are only two equally like possibilities — the other child is a girl or the other child is a boy, and so the probability of two boys is 1/2.

Paulos poses a “new variant of the two-boy problem”:

A couple has two children and we’re told that at least one of them is a boy born on a Tuesday. What is the probability the couple has two boys? Believe it or not, the Tuesday is important, and the answer is 13/27. If we discover the Tuesday birth in slightly different intensional [sic] contexts, however, the answer could be 1/3 or 1/2.

PROBLEM 2, with variations. Bloggers

No. 5. “[B]irth order is not part of the question, only whether the unidentified child is male or female, in which case the odds are 1 in 2 ….”

No. 7. Settembrini gives the calculations for the 13/27 problem.

No. 25, Ivan of NYC. “There is another version to the BG problem: suppose that in a family of two children, one is a girl named Emily. What is the probability that the other child is her sister? Turns out to be 1/2. (I was asked this question on an interview)”

### Discussion

1. How would you respond to Blogger 10's comment about needing more information?

2. With respect to blogger 20, suppose that you believe that there could not possibly be such a person as Linda. What would be the probability of a.)? The probability of b.)? Would Paulos be correct in this case?

3. How would you respond to Blogger 5's comment about birth order?

4. Without viewing Blogger 7’s calculations, calculate the answer to the 13/27 problem. Do you agree with Blogger 7's calculations?

5. Do you agree with Blogger 25 about the probability when you know one child's name?

Submitted by Margaret Cibes

## Student learning lags over summers

“The Case Against Summer Vacation”

by David Von Drehle, *TIME*, Thursday, July 22, 2010

This article describes research about the effect on learning of long summer vacations for U.S. school children, especially for, but not limited to, low-income children without access to activities such as camp, travel, or other enrichment experiences.

[W]hen American students are competing with children around the world, who are in many cases spending four weeks longer in school each year, larking through summer is a luxury we can't afford. …. By the time the bell rings on a new school year, the poorer kids have fallen weeks, if not months, behind. And even well-off American students may be falling behind their peers around the world. …. "We expect that athletes and musicians would see their performance suffer without practice. Well, the same is true of students, [says one educational administrator]."

The article provides two graphics, neither of which is online now. The first was a time-series graph showing the gap among low-, middle-, and high-income math test scores over grades 1 through 5; the contributor (cibesm@comcast.net) has an electronic copy for interested readers. The second was a bar chart containing the following data. (No information was given about the instrument on which the math scores were based or the number of students who were tested in each country.)

Country-School Year (median days)-Total Instructional Hours-Math Scores (15-year-olds)

South Korea-204-545-547

Japan-200-600-523

Denmark-200-648-513

Brazil-200-800-370

Mexico-200-1047-406

Australia-197-815-520

New Zealand-194-968-522

Germany-193-758-504

Norway-190-654-490

U.S.-180-1080-474

Luxembourg-176-642-490

Spain-176-713-480

Russia-169-845-476

Italy-167-601-462

### Discussion

For each country, assume that similarly large numbers of students in each country took a common math test and that median days in a school year was a pretty accurate representation of the length of the school year across that country.

1. Given that the correlation between median days in a school year and total instructional hours is about -0.007, what might you conclude about the relationship between days and hours in a school year? Suggest an explanation for this.

2. Sketch a graph of median days in a school year as the explanatory variable and math scores as the response variable.

a. The data points for which two countries fall outside of the relatively linear pattern of the other twelve countries?

b. Without those two data points, the correlation increases from about +0.108 to about +0.919. Can you think of any legitimate reason to omit them in order to report (with an appropriate note) a stronger correlation? What else might you want to know in order to decide?

c. The author suggests that spending 4 weeks longer in school might improve U.S. math scores. Do you see any evidence *here* that extending the U.S. school year by 4 weeks (20 school days) would improve U.S. math scores?

3. Given that the correlation between total instructional hours and math scores is about -0.397, what does this *number alone* imply about the relationship between hours in a school year and math scores? Do you see any evidence *here* that increasing hours would improve U.S. math scores?

4. For each country, a blogger calculated the total instructional hours of teaching required to increase a math score by 1 point and concluded, “The US is more efficient in its teaching then Mexico and Brazil.”

a. The U.S. has more instructional hours per point than most other countries shown. Do you agree that this higher ratio indicates more "efficiency"?

b. Do you agree with the blogger’s arithmetic with respect to his ordering of the U.S., Mexico, and Brazil ratios?

c. What, if anything, might the U.S. rank with respect to these ratios suggest about U.S. teachers and/or students, compared to those of other countries?

5. What other information and/or data might be helpful to decision-makers considering a decision about increasing the length of the U.S. school year?

Submitted by Margaret Cibes

## Facebook data on relationship breakups

Using Facebook Updates to Chronicle Breakups, Nick Bilton, The New York Times Bits Blog, November 3, 2010.

David McCandless has a hobby that many would find odd, but perhaps not too odd to readers of Chance News.

David McCandless, a London-based author, writer and designer, is constantly playing with data sets available online and translating heaps of code into well-designed visual stories. Some of Mr. McCandless’s notable projects include visualizing the billions of dollars spent by people and governments around the world and visually explaining the different views of United States politicians, divided by their political predilection.

Facebook, a social network site, has data on relationship status: single, in a relationship, married, it's complicated, etc. With the help of Lee Byron of Facebook, he produced the following graph on breakups by looking at changes in relationship status.

The repeated peaks are Mondays, a day at higher risk of breakups. The general findings are that

most breakups occur three times in the year — in the weeks leading up to spring breaks, right before the start of the summer holidays and a couple of weeks before Christmas.

### Questions

1. Changing one's status in Facebook is a surrogate measure of the actual ending of a relationship. What limitations does this produce in this data set?

2. Mr. McCandless claims that "people tend to break up with their significant others on Mondays, presumably after a weekend grapple." Is there an alternate explanation for the spike of breakups on Monday?

Submitted by Steve Simon

## National polling 2010

“How Did The Polls Do?”

by Mark Blumenthal, *HUFFPOST POLLSTER*, November 3, 2010

Blumenthal summarizes his initial impressions of the 2010 polling efforts:

On average, the final statewide pre-election polls once again provided a largely unbiased measurement of the outcomes of most races, Congressional District polling had a slight Democratic skew, national polls that sampled both landline and cell phones measured national Congressional vote preference more accurately than those that sampled only landline phones and the venerable Gallup Poll took one on the chin. .... Gallup's error on the margin will likely be its biggest since it started asking the generic vote question 60 years ago.

http://images.huffingtonpost.com/2010-11-03-Blumenthal-Generic2Party1103.png

Submitted by Margaret Cibes

## Nevada polling 2010

“Not All Polls Were Wrong In Nevada”

By Mark Blumenthal, *HUFFPOST POLLSTER*, November 6, 2010

Whilepublicmedia polls in late October consistently gave a slight advantage to Republican Senate challenger Sharron Angle, theinternal campaignpolls gave Democrat Harry Reid the edge and campaign pollsters on both sides attribute the difference to a combination of greater care in modeling the demographics of the electorate, more persistence in reaching all sampled voters and the added value of registered voter lists. [contributor's emphasis]

Candidate pollsters also attributed their successes to maintaining a *constant* model of the distribution of voters (by age, gender, race, region) across the surveys, having available rich data sets of past voter behavior, insisting on multiple callbacks to reach pre-identified but unavailable voters instead of relying on random-digit dialing or settling for phone answerers, and using hand-dialed cell phone numbers despite the additional work required. (Random-digit dialing to cell phones is banned by federal regulation.)

### Discussion

1. Explain, and/or comment on, the following statement by the author:

While none of the margins on any one poll was large enough to attain statistical significance, the consistency of the results demonstrates that Angle's advantages did not occur by chance alone.

2. Do you agree with this statement by the author?

Our final "trend estimate" gave Angle a nearly three-point lead (48.8% to 46.0%) -- enough to classify the race as "lean Republican."

Submitted by Margaret Cibes

## Galton board video

This is a nice YouTube video showing how the action of beads falling through an assortment of pins resembles the behavior of 5,000-6,000 monthly returns of the IFA Index Portfolio 100 over 50 years (through 2008).

There are three parts to the machine: (a) a fixed, drawn bell curve superimposed on glass over (b) a physical bar chart of thousands of beads representing the last 50 years of monthly average returns, and (c) a physical device randomly dropping beads through pins above the bar chart. A voiceover narrates the action of the falling beads, which is described as random.

### Discussion

Comment on the following (spelling-edited) blogs[4].

1. “How is it random if all the beads are funneled into the center already. If a bead doesn’t start towards the right side, it’s never going to reach the right side.”

2. “Random would be an even distribution across the board. Random implies NO PATTERN …but this is clearly a pattern.”

Submitted by Margaret Cibes

## Remarkable birthday pattern, or not?

“Mom’s babies born on 8-8-08, 9-9-09, 10-10-10”

by Elizabeth Weise, USA TODAY, October 14, 2010

The article quotes a University of Oregon biostatistician:

While the dates might seem “incredibly rare,” they're really not. Such a lineup can only happen in the first 12 years of the century and at least 10 months apart. …. Given that the first birth occurred in that window, the probability is not as astronomical as you might be compelled to think.</blockkquote>And a Berkeley statistician states:

[I]t's not that high a number at all. …. The 'chance' you get depends on the assumptions you make. …. One set of assumptions gives a chance of about 1 in 50 million. More realistic assumptions — including allowing at least 11 months between births — increases it to about 1 in 2,500. Since thousands of women in the United States had kids in 2008, 2009 and 2010, this suddenly seems a little less extraordinary.## Question

1. Estimate the probability of these three birthdays, based on the Oregon professor’s statement.

Submitted by Margaret Cibes

2. Can you confirm the Berkeley statistician’s figure of 1 in 2,500, based on his assumption?

3. How might the Berkeley statistician have arrived at the 1 in 50 million figure?